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Transformer Short-Circuit Current Calculator

Estimate the prospective three-phase fault current at a transformer secondary from kVA, voltage and impedance.

READY FOR YOUR DATA

Enter your values, then select Calculate.

Formula & assumptions

Rated current = kVA × 1000 / (√3 × V). Prospective fault current Isc = rated current × 100 / Z%. Fault level (MVA) = kVA / (Z% × 10).

This assumes an infinitely strong upstream supply and ignores cable and busbar impedance, motor contribution and arc resistance, so the real fault current is lower at a downstream point and motor contribution can add to it. It is an estimate of the maximum at the transformer terminals, not a protection study. Use a complete short-circuit study for equipment ratings.

Calculation reviewed: 4 October 2026 · Engineering Desk Tools

How to use the Transformer short-circuit current calculator

Estimate the prospective three-phase fault current at a transformer secondary from kVA, voltage and impedance. Start with measurements or documented values for the equipment and reporting period you actually want to assess. The calculator does not fill in a typical installation for you. Its blank fields help keep a demonstration value from being mistaken for your own operating data.

Choose the required options, enter the values in the labelled units and select Calculate. If a field is rejected, check its range and unit before changing it. The result is accompanied by the equation and assumptions so you can decide whether it answers your engineering question.

Inputs and measurement basis

Record the measurement source and operating condition. Retain unrounded values for verification.

Method and interpretation

At the transformer secondary, the maximum fault current is limited mainly by the transformer impedance, shown as a percentage on the nameplate. With an infinitely strong supply the fault current equals rated current divided by the per-unit impedance, so a 5 percent impedance gives twenty times rated current. Cable and busbar impedance lower the value farther downstream, while running motors can add current.

Rated current = kVA × 1000 / (√3 × V). Prospective fault current Isc = rated current × 100 / Z%. Fault level (MVA) = kVA / (Z% × 10).

This assumes an infinitely strong upstream supply and ignores cable and busbar impedance, motor contribution and arc resistance, so the real fault current is lower at a downstream point and motor contribution can add to it. It is an estimate of the maximum at the transformer terminals, not a protection study. Use a complete short-circuit study for equipment ratings.

Worked example

This example does not populate the form. Enter your own installation data.

InputExample value
Transformer rating (kVA)1000
Secondary line voltage (V)400
Transformer impedance (%)5

Calculated result: 28.8675 kA prospective fault current. Upper-bound estimate at the transformer terminals. Verify equipment short-circuit ratings with a full study.

Check the arithmetic independently using the displayed equation. Retain intermediate precision and compare the final value with your equipment documentation.

Quick-reference table

Illustrative calculated values, not equipment ratings. Other assumptions stay as stated in the worked example.
Changed inputCalculated result
Transformer rating (kVA): 50014.4338 kA prospective fault current
Transformer rating (kVA): 1,00028.8675 kA prospective fault current
Transformer rating (kVA): 1,50043.3013 kA prospective fault current

These illustrative rows retain the worked example assumptions except for the varied input. They are not certified ratings or manufacturer data. Use the form for intermediate values.

Common mistakes

Using the primary voltage; entering impedance as a decimal instead of a percentage; treating the transformer-terminal value as the fault level at every downstream board; using this estimate to rate equipment without a full study. Before relying on the output, check the decimal format, unit scale and source of each value. Recheck unusual results against the formula.

Frequently asked questions

Are the example values used automatically?

No. Inputs remain blank when the tool opens or when you clear them. The worked example and table are reading material below the calculator. Enter the actual values you want to check each time, and label saved reports so their context is not lost.

What does the result mean?

The result is the highest three-phase fault current at the transformer secondary with an infinitely strong supply. Points downstream see less, and equipment must be rated above the real fault level from a full study.

Can I use a zero or a negative value?

The allowed range follows the meaning of each input. A divisor needs a positive value; other fields may allow zero. Check the form labels and error message rather than forcing an invalid value. A rejected input must be corrected before a result can be shown.

Is this a final design or equipment approval?

No. This assumes an infinitely strong upstream supply and ignores cable and busbar impedance, motor contribution and arc resistance, so the real fault current is lower at a downstream point and motor contribution can add to it. It is an estimate of the maximum at the transformer terminals, not a protection study. Use a complete short-circuit study for equipment ratings. Use the calculation as support for a checked decision, and review equipment documentation and applicable requirements before changing an installation or operating setting.

How can I save or share a calculation?

Calculate first, then use Copy result or Print report. Some maintenance tools also provide a CSV summary. Reports contain your own entered data, so review them before sharing. You can share the public page URL without including plant records or confidential measurements.

How do I report an unexpected result?

Use the Contact page and include the tool URL, input values, units, expected output and the reference you used. Explain the measurement basis. Exclude confidential information.

Related tools and records

Use related calculations with consistent units, periods and equipment scope.

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